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Move deprecations along: std.range.hasLength

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Sebastian Wilzbach 2017-12-13 07:25:44 +01:00
parent b5cdcc99e1
commit b97afe2016
1 changed files with 1 additions and 29 deletions
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30
std/range/primitives.d
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@ -1388,41 +1388,13 @@ This is because a narrow string's length does not reflect the number of
characters, but instead the number of encoding units, and as such is not useful
with range-oriented algorithms. To use strings as random-access ranges with
length, use $(REF representation, std, string) or $(REF byCodeUnit, std, utf).
Deprecation: Historically `hasLength!R` yielded `true` for types whereby
`R.length` returns other types convertible to `ulong`, such as `int`, `ushort`,
`const(size_t)`, user-defined types using `alias this`, or notably `ulong` on
32-bit systems. This behavior has been deprecated. After December 2017,
`hasLength` will yield `true` only if `R.length` yields the exact type `size_t`.
*/
template hasLength(R)
{
static if (is(typeof(((R* r) => r.length)(null)) Length))
{
static if (is(Length == size_t))
{
enum bool hasLength = !isNarrowString!R;
}
else static if (is(Length : ulong))
{
// @@@DEPRECATED_2017-12@@@
// Uncomment the deprecated(...) message and take the pragma(msg)
// out once https://issues.dlang.org/show_bug.cgi?id=10181 is fixed.
pragma(msg, __FILE__ ~ "(" ~ __LINE__.stringof ~
"): Note: length must have type size_t on all systems" ~
", please update your code by December 2017.");
//deprecated("length must have type size_t on all systems")
enum bool hasLength = true;
}
else
{
enum bool hasLength = false;
}
}
enum bool hasLength = is(Length == size_t) && !isNarrowString!R;
else
{
enum bool hasLength = false;
}
}
///