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fix issue 12470 - std.array.replace does not work with inout(char)[]

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Basile Burg 2017-09-13 20:08:01 +02:00
parent bb1e6f9d50
commit 722ecd878c
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1 changed files with 11 additions and 1 deletions
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12
std/algorithm/searching.d
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@ -1887,7 +1887,7 @@ if (isForwardRange!R1 && isForwardRange!R2
Select!(haystack[0].sizeof == 1, ubyte[],
Select!(haystack[0].sizeof == 2, ushort[], uint[]));
// Will use the array specialization
static TO force(TO, T)(T r) @trusted { return cast(TO) r; }
static TO force(TO, T)(inout T r) @trusted { return cast(TO) r; }
return force!R1(.find!(pred, Representation, Representation)
(force!Representation(haystack), force!Representation(needle)));
}
@ -2096,6 +2096,16 @@ if (isForwardRange!R1 && isForwardRange!R2
assert([C(1,0), C(2,0), C(3,1), C(4,0)].find!"a.x == b"(SList!int(2, 3)[]) == [C(2,0), C(3,1), C(4,0)]);
}
@safe unittest // issue 12470
{
import std.array : replace;
inout(char)[] sanitize(inout(char)[] p)
{
return p.replace("\0", " ");
}
assert(sanitize("O\x00o") == "O o");
}
@safe unittest
{
import std.algorithm.comparison : equal;