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Fix Issue 21760 - std.conv.to does not know how to convert a string to a std.experimental.checkedint.Checked!T

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Nathan Sashihara 2021-03-24 09:12:31 -07:00 • committed by The Dlang Bot
parent 3c260553d1
commit 361b51cddf
1 changed files with 30 additions and 1 deletions
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31
std/experimental/checkedint.d
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@ -263,7 +263,8 @@ if (isIntegral!T || is(T == Checked!(U, H), U, H))
{
import std.algorithm.comparison : among;
import std.experimental.allocator.common : stateSize;
import std.traits : hasMember;
import std.range.primitives : isInputRange, ElementType;
import std.traits : hasMember, isSomeChar;
/**
The type of the integral subject to checking.
@ -378,6 +379,34 @@ if (isIntegral!T || is(T == Checked!(U, H), U, H))
assert(a == 3 && b == 3);
}
/**
Construct from a decimal string. The conversion follows the same rules as
$(REF to, std, conv) converting a string to the wrapped `T` type.
Params:
str = an $(REF_ALTTEXT input range, isInputRange, std,range,primitives)
of characters
*/
this(Range)(Range str)
if (isInputRange!Range && isSomeChar!(ElementType!Range))
{
import std.conv : to;
this(to!T(str));
}
/**
$(REF to, std, conv) can convert a string to a `Checked!T`:
*/
@system unittest
{
import std.conv : to;
const a = to!long("1234");
const b = to!(Checked!long)("1234");
assert(a == b);
}
// opCast
/**
Casting operator to integral, `bool`, or floating point type. If `Hook`