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Do not call bsf with 0

This commit is contained in:
Hackerpilot 2015-03-30 17:34:24 -07:00
parent e5832e6cd8
commit 469da17c36
1 changed files with 4 additions and 3 deletions
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7
src/dfmt/wrapping.d
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@ -55,7 +55,8 @@ struct State
{
immutable uint k = breaks >>> i;
immutable bool b = k == 0;
immutable size_t j = min(i + bsf(k) + 1, tokens.length);
immutable uint bits = b ? 0 : bsf(k);
immutable size_t j = min(i + bits + 1, tokens.length);
ll += tokens[i .. j].map!(a => tokenLength(a)).sum();
if (ll > config.columnSoftLimit)
{
@ -90,8 +91,8 @@ struct State
{
import core.bitop : bsf, popcnt;
if (_cost < other._cost || (_cost == other._cost && ((popcnt(breaks)
&& popcnt(other.breaks) && bsf(breaks) > bsf(other.breaks))
if (_cost < other._cost || (_cost == other._cost && ((breaks != 0
&& other.breaks != 0 && bsf(breaks) > bsf(other.breaks))
|| (_solved && !other.solved))))
{
return -1;